Fixed end moment

The fixed end moments are reaction moments developed in a beam member under certain load conditions with both ends fixed. A beam with both ends fixed is statically indeterminate to the 3rd degree, and any structural analysis method applicable on statically indeterminate beams can be used to calculate the fixed end..

Examples

In the following examples, clockwise moments are positive. The vertical reactions are not shown since they can be easily determined from statics.

Concentrated load of magnitude P	Linearly distributed load of maximum intensity q₀
Uniformly distributed load of intensity q	Couple of magnitude M₀

The two cases with distributed loads can be derived from the case with concentrated load by integration. For example, when a uniformly distributed load of intensity $q$ is acting on a beam, then an infinitely small part $dx$ distance $x$ apart from the left end of this beam can be seen as being under a concentrated load of magnitude $qdx$ . Then,

M_{\mathrm {right} }^{\mathrm {fixed} }=\int _{0}^{L}{\frac {qdx\,x^{2}(L-x)}{L^{2}}}={\frac {qL^{2}}{12}}

M_{\mathrm {left} }^{\mathrm {fixed} }=\int _{0}^{L}\left\{-{\frac {qdx\,x(L-x)^{2}}{L^{2}}}\right\}=-{\frac {qL^{2}}{12}}

Where the expressions within the integrals on the right hand sides are the fixed end moments caused by the concentrated load $qdx$ .

For the case with linearly distributed load of maximum intensity $q_0$ ,

M_{\mathrm {right} }^{\mathrm {fixed} }=\int _{0}^{L}q_{0}{\frac {x}{L}}dx{\frac {x^{2}(L-x)}{L^{2}}}={\frac {q_{0}L^{2}}{20}}

M_{\mathrm {left} }^{\mathrm {fixed} }=\int _{0}^{L}\left\{-q_{0}{\frac {x}{L}}dx{\frac {x(L-x)^{2}}{L^{2}}}\right\}=-{\frac {q_{0}L^{2}}{30}}

References

Yang, Chang-hyeon (2001-01-10). Structural Analysis (in Korean) (4th ed.). Seoul: Cheong Moon Gak Publishers. ISBN 89-7088-709-1.

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Fixed end moment

Examples

See also

References