2014 Sacramento Challenger – Doubles
Doubles | |
---|---|
2014 Sacramento Challenger | |
Champions |
|
Runners-up |
|
Final score | 6–3, 6–2 |
John-Patrick Smith and Matt Reid were the defending champions, however they chose not to participate with each other. Smith partners Adam Hubble, whilst Reid partners Jose Statham.
Adam Hubble and John-Patrick Smith won the title by defeating Peter Polansky and Adil Shamasdin 6–3, 6–2 in the final.
Seeds
Marcus Daniell / Artem Sitak (Semifinals) Peter Polansky / Adil Shamasdin (Final) Bradley Klahn / Tim Smyczek (withdrew) Sekou Bangoura / Tennys Sandgren (First round)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- w/o = Walkover
- r = Retired
- d = Defaulted
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | 6 | 77 | |||||||||||||||||||||||||
WC | 1 | 64 | 1 | 2 | 78 | [10] | |||||||||||||||||||||
Q | 3 | 3 | 6 | 66 | [4] | ||||||||||||||||||||||
6 | 6 | 1 | 4 | 77 | [14] | ||||||||||||||||||||||
PR/4 | 1 | 4 | PR | 6 | 65 | [16] | |||||||||||||||||||||
PR | 6 | 6 | PR | 6 | 66 | [10] | |||||||||||||||||||||
3 | 4 | 4 | 78 | [8] | |||||||||||||||||||||||
6 | 6 | PR | 6 | 6 | |||||||||||||||||||||||
5 | 6 | [10] | 2 | 3 | 2 | ||||||||||||||||||||||
WC | 7 | 4 | [2] | 6 | 4 | [7] | |||||||||||||||||||||
WC | 7 | 6 | WC | 4 | 6 | [10] | |||||||||||||||||||||
LL | 5 | 4 | WC | 4 | 2 | ||||||||||||||||||||||
6 | 4 | [8] | 2 | 6 | 6 | ||||||||||||||||||||||
PR | 3 | 6 | [10] | 2 | 4 | ||||||||||||||||||||||
66 | 0 | 2 | 6 | 6 | |||||||||||||||||||||||
2 | 77 | 6 |
References
This article is issued from
Wikipedia.
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