2013 Audi Melbourne Pro Tennis Classic – Doubles

Doubles
2013 Audi Melbourne Pro Tennis Classic
Champions United States Jan Abaza
United States Louisa Chirico
Runners-up United States Asia Muhammad
United States Allie Will
Final score 6–4, 6–4

Maria Fernanda Alves and Jessica Moore were the defending champions, having won the event in 2012, but they lost in the quarterfinals to Jan Abaza and Louisa Chirico.

Julia Cohen and Tatjana Maria, originally seeded second, withdrew before the tournament began and were not replaced. As a result, their opponents Shelby Rogers and Nicola Slater were given a bye into the second round.

Abaza and Chirico won the tournament, defeating Asia Muhammad and Allie Will in the final, 6–4, 6–4.

Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 United States I Falconi
United States M Sanchez
3 7 [10]
  United States E Harman
United States E Lumpkin
6 5 [12]   United States E Harman
United States E Lumpkin
3 7 [6]
Alt Japan M Hibi
United States D Starr
3 1   United States S Marand
United States N Pluskota
6 5 [10]
  United States S Marand
United States N Pluskota
6 6   United States S Marand
United States N Pluskota
3 0
4 Brazil MF Alves
Australia J Moore
6 7   United States J Abaza
United States L Chirico
6 6
WC United States V Bensimon
United States C Woodson
2 5 4 Brazil MF Alves
Australia J Moore
6 4 [7]
  United States J Abaza
United States L Chirico
1 6 [10]
  United States J Abaza
United States L Chirico
6 6
  United States J Elie
Australia S Peers
6 5 [10] 3 United States A Muhammad
United States A Will
4 4
  United States S Crawford
United States S Vickery
2 7 [6]   United States J Elie
Australia S Peers
63 2
3 United States A Muhammad
United States A Will
77 6
3 United States A Muhammad
United States A Will
7 6
  Italy A Brianti
United States A Riske
6 5 [8]   United States S Rogers
United Kingdom N Slater
5 2
  Czech Republic K Kramperová
Belarus I Kremen
4 7 [10]   Czech Republic K Kramperová
Belarus I Kremen
4 2
  United States S Rogers
United Kingdom N Slater
6 6

References

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.