2006 ATP Buenos Aires – Doubles

Doubles
2006 ATP Buenos Aires
Champions	František Čermák Leoš Friedl
Runners-up	Vasilis Mazarakis Boris Pašanski
Final score	6–1, 6–2

František Čermák and Leoš Friedl were the defending champions.

Čermák and Friedl successfully defended their title, defeating Vasilis Mazarakis and Boris Pašanski 6–1, 6–2 in the final.

Seeds

Draw

Draw

	First Round							Quarterfinals							Semifinals							Final
	1	F Čermák L Friedl	6	6
		D Škoch J Vaněk	1	2				1	F Čermák L Friedl	6	5	[11]
		A Montañés A Portas	3	0					C Berlocq P Starace	2	7	[9]
		C Berlocq P Starace	6	6											1	F Čermák L Friedl	5	6	[11]
	3	M García S Prieto	6	6												A Martín F Vicente	7	3	[9]
		N Almagro T Cibulec	3	1				3	M García S Prieto	5	64
	WC	JM del Potro J Mónaco	3	6	[7]				A Martín F Vicente	7	77
		A Martín F Vicente	6	3	[10]																	1	F Čermák L Friedl	6	6
	WC	E Massa L Mayer	2	6	[5]																		V Mazarakis B Pašanski	1	2
		O Patience F Serra	6	2	[10]				O Patience F Serra
		A di Mauro F Volandri	2	3				4	A Calleri G Etlis	w/o
	4	A Calleri G Etlis	6	6											4	A Calleri G Etlis
		M Daniel F Saretta	62	6	[8]											V Mazarakis B Pašanski	w/o
		V Mazarakis B Pašanski	77	1	[10]				V Mazarakis B Pašanski	4	6	[12]
		JC Ferrero S Ventura	6	6					JC Ferrero S Ventura	6	4	[10]
	2	M Fyrstenberg M Matkowski	4	3

References

• Draw