1959 Wimbledon Championships – Girls' Singles

Girls' Singles
1959 Wimbledon Championships
Champion South Africa Joan Cross
Runner-up Austria Doris Schuster
Final score 6–1, 6–1

Joan Cross defeated Doris Schuster in the final, 6–1, 6–1 to win the Girls' Singles tennis title at the 1959 Wimbledon Championships.[1]

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
South Africa Joan Cross 6 6
Republic of Ireland J Atkinson 1 1
South Africa Joan Cross 6 6
Denmark S Westh 6 6 Denmark S Westh 1 0
Switzerland M Berli 2 4 Denmark S Westh 2 6 6
Belgium Micheline Ruquois 6 6 Belgium Micheline Ruquois 6 4 4
Netherlands Marjan Moritz 2 3 South Africa Joan Cross 6 6
Poland E Nowopolska 0 0 Austria Doris Schuster 1 1
Austria Doris Schuster 6 6 Austria Doris Schuster 6 6
India D Appiah 6 7 India D Appiah 4 2
Norway B Sønderaal 2 5 Austria Doris Schuster 7 4 6
United Kingdom Carol Webb 5 6 3
France F Marsot 1 0
United Kingdom Carol Webb 6 6

References

  1. "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
  • Source for the draw at Wimbledon.com
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