1958 NFL playoffs

The 1958 National Football League season resulted in a tie for the Eastern Conference championship between the Cleveland Browns and the New York Giants, requiring a one-game playoff to be held between them. This conference championship game was played on December 21, 1958, at Yankee Stadium. The winner of that game then hosted the Baltimore Colts on December 28.

Tournament bracket

New York Giants 10, Cleveland Browns 0

	1	2	3	4	Total
Browns	0	0	0	0	0
Giants	7	3	0	0	10

at Yankee Stadium in The Bronx, New York City

Game information

First Quarter

Second Quarter

Third Quarter

Fourth Quarter

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.

NFL playoffs
Conference tiebreakers
1941 1943 1947 1950 1952 1957 1958 1965
NFL playoff system
1967 1968 1969
1970–71 1971–72 1972–73 1973–74 1974–75 1975–76 1976–77 1977–78 1978–79 1979–80
1980–81 1981–82 1982–83 1983–84 1984–85 1985–86 1986–87 1987–88 1988–89 1989–90
1990–91 1991–92 1992–93 1993–94 1994–95 1995–96 1996–97 1997–98 1998–99 1999–00
2000–01 2001–02 2002–03 2003–04 2004–05 2005–06 2006–07 2007–08 2008–09 2009–10
2010–11 2011–12 2012–13 2013–14 2014–15 2015–16 2016–17 2017–18 2018–19
American Football League playoffs
Post-season streaks Post-season droughts AFC Championship Game broadcasters AFL Championship Game broadcasters NFC Championship Game broadcasters NFL Championship Game broadcasters Playoff Bowl broadcasters Super Bowl broadcasters NFL playoff results NFL playoff games NFL starting quarterback playoff records Head coaches by playoff record