1955 Wimbledon Championships – Girls' Singles

Girls' Singles
1955 Wimbledon Championships
Champion United Kingdom Sheila Armstrong
Runner-up France Béatrice de Chambure
Final score 6–2, 6–4

Sheila Armstrong defeated Béatrice de Chambure in the final, 6–2, 6–4 to win the Girls' Singles tennis title at the 1955 Wimbledon Championships.[1]

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
Denmark T Dahl 0 3
Australia W Middleton 6 6
Australia W Middleton 4 4
France Béatrice de Chambure 6 6 France Béatrice de Chambure 6 6
Republic of Ireland Gene Hogan 0 0 France Béatrice de Chambure 6 6
West Germany G Stelges 4 10 3 Netherlands Fredy Marinkelle 0 1
Netherlands Fredy Marinkelle 6 8 6 France Béatrice de Chambure 2 4
United Kingdom Sheila Armstrong 6 6 United Kingdom Sheila Armstrong 6 6
Norway B Lorentzen 0 1 United Kingdom Sheila Armstrong 6 7
Jamaica D Crampton 7 2 Belgium MN Fossion 1 5
Belgium MN Fossion 9 6 United Kingdom Sheila Armstrong 6 6
South Africa Valerie Koortzen 3 2
South Africa Valerie Koortzen 6 6
Sweden L Engdahl 0 2

References

  1. "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
  • Source for the draw at Wimbledon.com
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