1928 U.S. National Championships – Women's Singles

Women's Singles
1928 U.S. National Championships
Champion United States Helen Wills
Runner-up United States Helen Jacobs[1]
Final score 6–2, 6–1

First-seeded Helen Wills defeated Helen Jacobs 6–2, 6–1 in the final to win the Women's Singles tennis title at the 1928 U.S. National Championships. The event was held at the West Side Tennis Club, Forest Hills, New York City. It was Will's fifth U.S. National singles title and her second in a row.[1]

Seeds

The tournament assigned eight seeded players for the women's singles event. Helen Wills is the champion; others show in brackets the round in which they were eliminated.

  1. United States Helen Wills (Champion)
  2. United States Molla Mallory (Semifinalist)
  3. United States Helen Jacobs (Finalist)
  4. United States Edith Cross (Semifinalist)
  5. United States Charlotte Chapin (Quarterfinalist)
  6. United States Marjorie Morrill (Quarterfinalist)
  7. United States Penelope Anderson (Quarterfinalist)
  8. United States May Sutton Bundy (Third round)

Draw

Final eight

Quarterfinals Semifinals Finals
               
1 United States Helen Wills 6 6
5 United States Charlotte Chapin 2 4
1 United States Helen Wills 6 6
4 United States Edith Cross 0 1
United States Hazel Wightman 3 4
4 United States Edith Cross 6 6
1 United States Helen Wills 6 6
3 United States Helen Jacobs 2 1
3 United States Helen Jacobs 6 6
5 United States Penelope Anderson 4 1
3 United States Helen Jacobs 6 7
2 United States Molla Mallory 2 5
6 United States Marjorie Morrill 2 6 3
2 United States Molla Mallory 6 3 6

References

  1. 1 2 Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 469. ISBN 978-0942257700.
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