Basic Algebra/Introduction to Basic Algebra Ideas/Chapter Test

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Section A (5 marks)[edit]

Evaluate the following expressions.

24\div 6-7=

(5+3)\times 6=

{\frac {16+14}{5}}-3=

{\frac {36}{4-(-2)}}+5=

\left({\frac {2\times 27}{9}}\right)^{2}=

Section B (5 marks)[edit]

Evaluate the following expressions.

9+3^{2}=

3+{\frac {20}{2^{2}}}=

{\frac {2(3+4)}{94^{0}}}=

20-2\left({\frac {96}{4^{2}}}\right)=

-4+5\left({\frac {56+7}{3^{2}}}\right)-1=

Section C (5 marks)[edit]

Evaluate the following expressions when $w=4$ , $x=5$ , $y=6$ and $z=7$ .

3x+2y+z=

{\frac {w^{2}}{y+2}}+2z=

2\left({\frac {x^{2}+3}{w}}\right)-(2y-z)=

(6-3)\left({\frac {2w-x}{z-4}}\right)+(3y-4)=

3^{2}(2w^{0})\left({\frac {wx}{y-2}}\right)-z=

Section D (6 marks)[edit]

Evaluate the value of $x$ in the following equations with the given value of $y$ .

x=

x=

18

$2\left({\frac {2x-2}{y-3}}\right)+8=6^{2}$ (given $y=7$ )

x=

19

$3^{3}+2^{0}+3x-2y\left({\frac {18}{2}}\right)=97$ (given $y=3$ )

x=

x\in \{

,

\}

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